In case you're wondering, yes, x^2*y^2 will always equal c^2 where x, y, and c are all integers. I know this question was just eating you up, so let me tell you how I know:
x^2*y^2 = (x*x)*(y*y) = (x*y)*(x*y) = (x*y)^2
So, more specifically, c=x*y.
Look, I just know what the people want to know, and I feel it incumbent on me to give it to them.
Tuesday, January 26, 2010
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